c/3c+5=23

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Solution for c/3c+5=23 equation: 



c/3c+5=23

We move all terms to the left:

c/3c+5-(23)=0



Domain of the equation: 3c!=0

c!=0/3

c!=0

c∈R



We add all the numbers together, and all the variables

c/3c-18=0

We multiply all the terms by the denominator


c-18*3c=0

Wy multiply elements

c-54c=0

We add all the numbers together, and all the variables

-53c=0

c=0/-53

c=0

Równanie nie ma rozwiązania

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