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5(2x-4)=3(1-3x)
We move all terms to the left:
5(2x-4)-(3(1-3x))=0
We add all the numbers together, and all the variables
5(2x-4)-(3(-3x+1))=0
We multiply parentheses
10x-(3(-3x+1))-20=0
We calculate terms in parentheses: -(3(-3x+1)), so:We get rid of parentheses
3(-3x+1)
We multiply parentheses
-9x+3
Back to the equation:
-(-9x+3)
10x+9x-3-20=0
We add all the numbers together, and all the variables
19x-23=0
We move all terms containing x to the left, all other terms to the right
19x=23
x=23/19
x=1+4/19
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