c-4=2+3(5c+2)

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Solution for c-4=2+3(5c+2) equation: 



c-4=2+3(5c+2)

We move all terms to the left:

c-4-(2+3(5c+2))=0



We calculate terms in parentheses: -(2+3(5c+2)), so:

2+3(5c+2)

determiningTheFunctionDomain
3(5c+2)+2

We multiply parentheses

15c+6+2

We add all the numbers together, and all the variables

15c+8

Back to the equation:

-(15c+8)



We get rid of parentheses

c-15c-8-4=0

We add all the numbers together, and all the variables

-14c-12=0

We move all terms containing c to the left, all other terms to the right

-14c=12

c=12/-14

c=-6/7

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