3n+119=n(8-6)

Solution for 3n+119=n(8-6) equation:

3n+119=n(8-6)

We move all terms to the left:

3n+119-(n(8-6))=0

We add all the numbers together, and all the variables

3n-(n2)+119=0

We add all the numbers together, and all the variables

-1n^2+3n+119=0

a = -1; b = 3; c = +119;
Δ = b2-4ac
Δ = 32-4·(-1)·119
Δ = 485
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{485}}{2*-1}=\frac{-3-\sqrt{485}}{-2}
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{485}}{2*-1}=\frac{-3+\sqrt{485}}{-2}
$