c-2/c+3=5

Solution for c-2/c+3=5 equation:

c-2/c+3=5

We move all terms to the left:

c-2/c+3-(5)=0


Domain of the equation: c!=0

c∈R


We add all the numbers together, and all the variables

c-2/c-2=0

We multiply all the terms by the denominator


c*c-2*c-2=0

We add all the numbers together, and all the variables

-2c+c*c-2=0

Wy multiply elements

c^2-2c-2=0

a = 1; b = -2; c = -2;
Δ = b2-4ac
Δ = -22-4·1·(-2)
Δ = 12
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{12}=\sqrt{4*3}=\sqrt{4}*\sqrt{3}=2\sqrt{3}$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{3}}{2*1}=\frac{2-2\sqrt{3}}{2}
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{3}}{2*1}=\frac{2+2\sqrt{3}}{2}
$