7x-(3x+5)-8=1/2(8x=20)-7x+5

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Solution for 7x-(3x+5)-8=1/2(8x=20)-7x+5 equation: 



7x-(3x+5)-8=1/2(8x=20)-7x+5

We move all terms to the left:

7x-(3x+5)-8-(1/2(8x)=0



Domain of the equation: 28x-8!=0

We move all terms containing x to the left, all other terms to the right

28x!=8

x!=8/28

x!=2/7

x∈R



We get rid of parentheses

7x-3x-(1/28x-8-5=0

We multiply all the terms by the denominator


7x*28x-3x*28x-8-5-8-5-(1=0

We add all the numbers together, and all the variables

7x*28x-3x*28x=0

Wy multiply elements

196x^2-84x^2=0

We add all the numbers together, and all the variables

112x^2=0

a = 112; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·112·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{224}=0$

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