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1/5x-60=2x-2
We move all terms to the left:
1/5x-60-(2x-2)=0
Domain of the equation: 5x!=0We get rid of parentheses
x!=0/5
x!=0
x∈R
1/5x-2x+2-60=0
We multiply all the terms by the denominator
-2x*5x+2*5x-60*5x+1=0
Wy multiply elements
-10x^2+10x-300x+1=0
We add all the numbers together, and all the variables
-10x^2-290x+1=0
a = -10; b = -290; c = +1;
Δ = b2-4ac
Δ = -2902-4·(-10)·1
Δ = 84140
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{84140}=\sqrt{4*21035}=\sqrt{4}*\sqrt{21035}=2\sqrt{21035}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-290)-2\sqrt{21035}}{2*-10}=\frac{290-2\sqrt{21035}}{-20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-290)+2\sqrt{21035}}{2*-10}=\frac{290+2\sqrt{21035}}{-20} $
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