c+32=3c+28

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Solution for c+32=3c+28 equation: 



c+32=3c+28

We move all terms to the left:

c+32-(3c+28)=0

We get rid of parentheses

c-3c-28+32=0

We add all the numbers together, and all the variables

-2c+4=0

We move all terms containing c to the left, all other terms to the right

-2c=-4

c=-4/-2

c=+2

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