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-1x+9/5x=1
We move all terms to the left:
-1x+9/5x-(1)=0
Domain of the equation: 5x!=0We multiply all the terms by the denominator
x!=0/5
x!=0
x∈R
-1x*5x-1*5x+9=0
Wy multiply elements
-5x^2-5x+9=0
a = -5; b = -5; c = +9;
Δ = b2-4ac
Δ = -52-4·(-5)·9
Δ = 205
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{205}}{2*-5}=\frac{5-\sqrt{205}}{-10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{205}}{2*-5}=\frac{5+\sqrt{205}}{-10} $
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