b2=9/441

Solution for b2=9/441 equation:

b2=9/441

We move all terms to the left:

b2-(9/441)=0

We add all the numbers together, and all the variables

b2-(+9/441)=0

We add all the numbers together, and all the variables

b^2-(+9/441)=0

We get rid of parentheses

b^2-9/441=0

We multiply all the terms by the denominator


b^2*441-9=0

Wy multiply elements

441b^2-9=0

a = 441; b = 0; c = -9;
Δ = b2-4ac
Δ = 02-4·441·(-9)
Δ = 15876
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{15876}=126$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-126}{2*441}=\frac{-126}{882}
=-1/7
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+126}{2*441}=\frac{126}{882}
=1/7
$