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1/5(4x+3)=5/6x-1x=
We move all terms to the left:
1/5(4x+3)-(5/6x-1x)=0
Domain of the equation: 5(4x+3)!=0
x∈R
Domain of the equation: 6x-1x)!=0We add all the numbers together, and all the variables
x∈R
1/5(4x+3)-(-1x+5/6x)=0
We get rid of parentheses
1/5(4x+3)+1x-5/6x=0
We calculate fractions
1x+6x/(120x^2+90x)+(-25x4/(120x^2+90x)=0
We calculate terms in parentheses: +(-25x4/(120x^2+90x), so:
-25x4/(120x^2+90x
We multiply all the terms by the denominator
-25x4
We add all the numbers together, and all the variables
-25x^4
We do not support expression: x^4
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