b2=3/16=5/16

Solution for b2=3/16=5/16 equation:

b2=3/16=5/16

We move all terms to the left:

b2-(3/16)=0

We add all the numbers together, and all the variables

b2-(+3/16)=0

We add all the numbers together, and all the variables

b^2-(+3/16)=0

We get rid of parentheses

b^2-3/16=0

We multiply all the terms by the denominator


b^2*16-3=0

Wy multiply elements

16b^2-3=0

a = 16; b = 0; c = -3;
Δ = b2-4ac
Δ = 02-4·16·(-3)
Δ = 192
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{192}=\sqrt{64*3}=\sqrt{64}*\sqrt{3}=8\sqrt{3}$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{3}}{2*16}=\frac{0-8\sqrt{3}}{32}
=-\frac{8\sqrt{3}}{32}
=-\frac{\sqrt{3}}{4}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{3}}{2*16}=\frac{0+8\sqrt{3}}{32}
=\frac{8\sqrt{3}}{32}
=\frac{\sqrt{3}}{4}
$