b2=1210

Solution for b2=1210 equation:

b2=1210

We move all terms to the left:

b2-(1210)=0

We add all the numbers together, and all the variables

b^2-1210=0

a = 1; b = 0; c = -1210;
Δ = b2-4ac
Δ = 02-4·1·(-1210)
Δ = 4840
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4840}=\sqrt{484*10}=\sqrt{484}*\sqrt{10}=22\sqrt{10}$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-22\sqrt{10}}{2*1}=\frac{0-22\sqrt{10}}{2}
=-\frac{22\sqrt{10}}{2}
=-11\sqrt{10}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+22\sqrt{10}}{2*1}=\frac{0+22\sqrt{10}}{2}
=\frac{22\sqrt{10}}{2}
=11\sqrt{10}
$