X+8=1/7x-2

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Solution for X+8=1/7x-2 equation:



X+8=1/7X-2
We move all terms to the left:
X+8-(1/7X-2)=0
Domain of the equation: 7X-2)!=0
X∈R
We get rid of parentheses
X-1/7X+2+8=0
We multiply all the terms by the denominator
X*7X+2*7X+8*7X-1=0
Wy multiply elements
7X^2+14X+56X-1=0
We add all the numbers together, and all the variables
7X^2+70X-1=0
a = 7; b = 70; c = -1;
Δ = b2-4ac
Δ = 702-4·7·(-1)
Δ = 4928
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{4928}=\sqrt{64*77}=\sqrt{64}*\sqrt{77}=8\sqrt{77}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(70)-8\sqrt{77}}{2*7}=\frac{-70-8\sqrt{77}}{14} $
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(70)+8\sqrt{77}}{2*7}=\frac{-70+8\sqrt{77}}{14} $

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