b/3+(-2)=3

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Solution for b/3+(-2)=3 equation: 



b/3+(-2)=3

We move all terms to the left:

b/3+(-2)-(3)=0

determiningTheFunctionDomain
b/3-3+(-2)=0

We add all the numbers together, and all the variables

b/3-5=0

We multiply all the terms by the denominator


b-5*3=0

We add all the numbers together, and all the variables

b-15=0

We move all terms containing b to the left, all other terms to the right

b=15

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