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(3x-9)(3x+1)=0
We multiply parentheses ..
(+9x^2+3x-27x-9)=0
We get rid of parentheses
9x^2+3x-27x-9=0
We add all the numbers together, and all the variables
9x^2-24x-9=0
a = 9; b = -24; c = -9;
Δ = b2-4ac
Δ = -242-4·9·(-9)
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{900}=30$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-30}{2*9}=\frac{-6}{18} =-1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+30}{2*9}=\frac{54}{18} =3 $
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