b-10=2(b+15-10)

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Solution for b-10=2(b+15-10) equation: 



b-10=2(b+15-10)

We move all terms to the left:

b-10-(2(b+15-10))=0

We add all the numbers together, and all the variables

b-(2(b+5))-10=0



We calculate terms in parentheses: -(2(b+5)), so:

2(b+5)

We multiply parentheses

2b+10

Back to the equation:

-(2b+10)



We get rid of parentheses

b-2b-10-10=0

We add all the numbers together, and all the variables

-1b-20=0

We move all terms containing b to the left, all other terms to the right

-b=20

b=20/-1

b=-20

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