12(b+2)=8(b+6)

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Solution for 12(b+2)=8(b+6) equation: 



12(b+2)=8(b+6)

We move all terms to the left:

12(b+2)-(8(b+6))=0

We multiply parentheses

12b-(8(b+6))+24=0



We calculate terms in parentheses: -(8(b+6)), so:

8(b+6)

We multiply parentheses

8b+48

Back to the equation:

-(8b+48)



We get rid of parentheses

12b-8b-48+24=0

We add all the numbers together, and all the variables

4b-24=0

We move all terms containing b to the left, all other terms to the right

4b=24

b=24/4

b=6

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