If it's not what You are looking for type in the equation solver your own equation and let us solve it.
b-(3(b+1)/5)=1
We move all terms to the left:
b-(3(b+1)/5)-(1)=0
We multiply all the terms by the denominator
b*5)-(3(b+1)-1*5)=0
We add all the numbers together, and all the variables
b*5)-(3(b+1)=0
Wy multiply elements
5b^2=0
a = 5; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·5·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$b=\frac{-b}{2a}=\frac{0}{10}=0$
| -3.2=3.2+w/4 | | b-3b+3/5=1 | | -9.9=-3.5+y/4 | | 3c+10=c-10 | | 1/2x+3/8=3/4x+42 | | 7x-1=5x-1= | | 2y=-4+12 | | 24-2m=4m-16 | | 11x-22=3x-1 | | B=36+26n=A32n | | -7d=-5d+10 | | 12-m=4m-24 | | 5(x-8)=32x+14 | | -7q+2=8-6q | | 3a-2a=+6 | | H/5=5.q | | -18=6+27k | | 17-3n-12=5 | | 3x-18=1/2x | | (x-20)=68 | | -7n=-6n-10 | | -16x+3x=-32+17x | | s/7.3=5.9 | | -16x+3x=-32 | | -4x+3-2x=8x+13 | | 4x+11=42 | | 20(0.25+d)+15d=18 | | -8-7q=-3q | | -1=13x | | a+5=11 | | 6=-3/x | | -1(-)7x=15x+21 |