b-3b+3/5=1

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Solution for b-3b+3/5=1 equation: 



b-3b+3/5=1

We move all terms to the left:

b-3b+3/5-(1)=0

determiningTheFunctionDomain
b-3b-1+3/5=0

We add all the numbers together, and all the variables

-2b-1+3/5=0

We multiply all the terms by the denominator


-2b*5+3-1*5=0

We add all the numbers together, and all the variables

-2b*5-2=0

Wy multiply elements

-10b-2=0

We move all terms containing b to the left, all other terms to the right

-10b=2

b=2/-10

b=-1/5

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