b-(-7)/3=3

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Solution for b-(-7)/3=3 equation: 



b-(-7)/3=3

We move all terms to the left:

b-(-7)/3-(3)=0

determiningTheFunctionDomain
b-3-(-7)/3=0

We multiply all the terms by the denominator


b*3-3*3-(-7)=0

We add all the numbers together, and all the variables

b*3-2=0

Wy multiply elements

3b-2=0

We move all terms containing b to the left, all other terms to the right

3b=2

b=2/3

b=2/3

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