4(2y+1)=2(y-3)

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Solution for 4(2y+1)=2(y-3) equation: 



4(2y+1)=2(y-3)

We move all terms to the left:

4(2y+1)-(2(y-3))=0

We multiply parentheses

8y-(2(y-3))+4=0



We calculate terms in parentheses: -(2(y-3)), so:

2(y-3)

We multiply parentheses

2y-6

Back to the equation:

-(2y-6)



We get rid of parentheses

8y-2y+6+4=0

We add all the numbers together, and all the variables

6y+10=0

We move all terms containing y to the left, all other terms to the right

6y=-10

y=-10/6

y=-1+2/3

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