b+2(b+5)=5(b-1)+1

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Solution for b+2(b+5)=5(b-1)+1 equation:


Simplifying
b + 2(b + 5) = 5(b + -1) + 1

Reorder the terms:
b + 2(5 + b) = 5(b + -1) + 1
b + (5 * 2 + b * 2) = 5(b + -1) + 1
b + (10 + 2b) = 5(b + -1) + 1

Reorder the terms:
10 + b + 2b = 5(b + -1) + 1

Combine like terms: b + 2b = 3b
10 + 3b = 5(b + -1) + 1

Reorder the terms:
10 + 3b = 5(-1 + b) + 1
10 + 3b = (-1 * 5 + b * 5) + 1
10 + 3b = (-5 + 5b) + 1

Reorder the terms:
10 + 3b = -5 + 1 + 5b

Combine like terms: -5 + 1 = -4
10 + 3b = -4 + 5b

Solving
10 + 3b = -4 + 5b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-5b' to each side of the equation.
10 + 3b + -5b = -4 + 5b + -5b

Combine like terms: 3b + -5b = -2b
10 + -2b = -4 + 5b + -5b

Combine like terms: 5b + -5b = 0
10 + -2b = -4 + 0
10 + -2b = -4

Add '-10' to each side of the equation.
10 + -10 + -2b = -4 + -10

Combine like terms: 10 + -10 = 0
0 + -2b = -4 + -10
-2b = -4 + -10

Combine like terms: -4 + -10 = -14
-2b = -14

Divide each side by '-2'.
b = 7

Simplifying
b = 7

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