3cos(2x)+sin(x)=1

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Solution for 3cos(2x)+sin(x)=1 equation: 


Simplifying
3cos(2x) + sin(x) = 1

Remove parenthesis around (2x)
3cos * 2x + sin(x) = 1

Reorder the terms for easier multiplication:
3 * 2cos * x + sin(x) = 1

Multiply 3 * 2
6cos * x + sin(x) = 1

Multiply cos * x
6cosx + sin(x) = 1

Multiply ins * x
6cosx + insx = 1

Solving
6cosx + insx = 1

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1insx' to each side of the equation.
6cosx + insx + -1insx = 1 + -1insx

Combine like terms: insx + -1insx = 0
6cosx + 0 = 1 + -1insx
6cosx = 1 + -1insx

Divide each side by '6osx'.
c = 0.1666666667o-1s-1x-1 + -0.1666666667ino-1

Simplifying
c = 0.1666666667o-1s-1x-1 + -0.1666666667ino-1

Reorder the terms:
c = -0.1666666667ino-1 + 0.1666666667o-1s-1x-1

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