b+2(4+2b)=15b+11

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Solution for b+2(4+2b)=15b+11 equation: 



b+2(4+2b)=15b+11

We move all terms to the left:

b+2(4+2b)-(15b+11)=0

We add all the numbers together, and all the variables

b+2(2b+4)-(15b+11)=0

We multiply parentheses

b+4b-(15b+11)+8=0

We get rid of parentheses

b+4b-15b-11+8=0

We add all the numbers together, and all the variables

-10b-3=0

We move all terms containing b to the left, all other terms to the right

-10b=3

b=3/-10

b=-3/10

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