abs(z-1)+abs(z+2)=2

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Solution for abs(z-1)+abs(z+2)=2 equation:


Simplifying
abs(z + -1) + abs(z + 2) = 2

Reorder the terms:
abs(-1 + z) + abs(z + 2) = 2
(-1 * abs + z * abs) + abs(z + 2) = 2
(-1abs + absz) + abs(z + 2) = 2

Reorder the terms:
-1abs + absz + abs(2 + z) = 2
-1abs + absz + (2 * abs + z * abs) = 2
-1abs + absz + (2abs + absz) = 2

Reorder the terms:
-1abs + 2abs + absz + absz = 2

Combine like terms: -1abs + 2abs = 1abs
1abs + absz + absz = 2

Combine like terms: absz + absz = 2absz
1abs + 2absz = 2

Solving
1abs + 2absz = 2

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Reorder the terms:
-2 + 1abs + 2absz = 2 + -2

Combine like terms: 2 + -2 = 0
-2 + 1abs + 2absz = 0

The solution to this equation could not be determined.

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