abs(z-1)+abs(z+1)=8

Solution for abs(z-1)+abs(z+1)=8 equation:

Simplifying
abs(z + -1) + abs(z + 1) = 8

Reorder the terms:
abs(-1 + z) + abs(z + 1) = 8
(-1 * abs + z * abs) + abs(z + 1) = 8
(-1abs + absz) + abs(z + 1) = 8

Reorder the terms:
-1abs + absz + abs(1 + z) = 8
-1abs + absz + (1 * abs + z * abs) = 8
-1abs + absz + (1abs + absz) = 8

Reorder the terms:
-1abs + 1abs + absz + absz = 8

Combine like terms: -1abs + 1abs = 0
0 + absz + absz = 8
absz + absz = 8

Combine like terms: absz + absz = 2absz
2absz = 8

Solving
2absz = 8

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Divide each side by '2bsz'.
a = 4b-1s-1z-1

Simplifying
a = 4b-1s-1z-1