abs(x-7)+abs(x-2)=5

Solution for abs(x-7)+abs(x-2)=5 equation:

Simplifying
abs(x + -7) + abs(x + -2) = 5

Reorder the terms:
abs(-7 + x) + abs(x + -2) = 5
(-7 * abs + x * abs) + abs(x + -2) = 5
(-7abs + absx) + abs(x + -2) = 5

Reorder the terms:
-7abs + absx + abs(-2 + x) = 5
-7abs + absx + (-2 * abs + x * abs) = 5
-7abs + absx + (-2abs + absx) = 5

Reorder the terms:
-7abs + -2abs + absx + absx = 5

Combine like terms: -7abs + -2abs = -9abs
-9abs + absx + absx = 5

Combine like terms: absx + absx = 2absx
-9abs + 2absx = 5

Solving
-9abs + 2absx = 5

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Reorder the terms:
-5 + -9abs + 2absx = 5 + -5

Combine like terms: 5 + -5 = 0
-5 + -9abs + 2absx = 0

The solution to this equation could not be determined.