abs(z-7)+abs(z-2)=5

Solution for abs(z-7)+abs(z-2)=5 equation:

Simplifying
abs(z + -7) + abs(z + -2) = 5

Reorder the terms:
abs(-7 + z) + abs(z + -2) = 5
(-7 * abs + z * abs) + abs(z + -2) = 5
(-7abs + absz) + abs(z + -2) = 5

Reorder the terms:
-7abs + absz + abs(-2 + z) = 5
-7abs + absz + (-2 * abs + z * abs) = 5
-7abs + absz + (-2abs + absz) = 5

Reorder the terms:
-7abs + -2abs + absz + absz = 5

Combine like terms: -7abs + -2abs = -9abs
-9abs + absz + absz = 5

Combine like terms: absz + absz = 2absz
-9abs + 2absz = 5

Solving
-9abs + 2absz = 5

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Reorder the terms:
-5 + -9abs + 2absz = 5 + -5

Combine like terms: 5 + -5 = 0
-5 + -9abs + 2absz = 0

The solution to this equation could not be determined.