abs((4x-5)/3)1

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Solution for abs((4x-5)/3)1 equation:


x in (-oo:+oo)

abs((4*x-5)/3) > 1 // - 1

abs((4*x-5)/3)-1 > 0

abs((4*x-5)/3)-1 > 0

x in (-oo:+oo)

abs((4*x-5)/3)

(4*x-5)/3 >= 0

( 3 )

3 >= 0

x należy do R

( 4*x-5 )

4*x-5 >= 0 // + 5

4*x >= 5 // : 4

x >= 5/4

(-oo:5/4) (5/4:+oo) 3 + + 4*x-5 - +

x in <5/4:+oo)

(4*x-5)/3-1 > 0

x in (-oo:5/4)

-((4*x-5)/3)-1 > 0

abs((4*x-5)/3)-1 > 0

/ | -((4*x-5)/3)-1 > 0 i x in (-oo:5/4) | (4*x-5)/3-1 > 0 i x in <5/4:+oo)

x in (-oo:5/4)

-((4*x-5)/3)-1 > 0

(-1*(4*x-5))/3-1 > 0

(-1*(4*x-5))/3+(-1*3)/3 > 0

-1*(4*x-5)-1*3 > 0

2-4*x > 0

(2-4*x)/3 > 0

(2-4*x)/3 > 0 // * 3^2

3*(2-4*x) > 0

( 2-4*x )

2-4*x > 0 // - 2

-4*x > -2 // : -4

x < -2/(-4)

x < 1/2

( 3 )

3 > 0

x należy do R

(-oo:1/2) (1/2:+oo) 2-4*x + - 3 + +

x in <5/4:+oo)

(4*x-5)/3-1 > 0

(4*x-5)/3+(-1*3)/3 > 0

4*x-1*3-5 > 0

4*x-8 > 0

(4*x-8)/3 > 0

(4*x-8)/3 > 0 // * 3^2

3*(4*x-8) > 0

( 3 )

3 > 0

x należy do R

( 4*x-8 )

4*x-8 > 0 // + 8

4*x > 8 // : 4

x > 8/4

x > 2

(-oo:2) (2:+oo) 3 + + 4*x-8 - +

x in (-oo:1/2) U (2:+oo)

(-oo:1/2) U (2:+oo)

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