abs(4x-5/3)1

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Solution for abs(4x-5/3)1 equation:


x in (-oo:+oo)

abs(4*x-(5/3)) > 1 // - 1

abs(4*x-(5/3))-1 > 0

abs(4*x-5/3)-1 > 0

abs(4*x-5/3)-1 > 0

x in (-oo:+oo)

abs(4*x-5/3)

4*x-5/3 >= 0

4*x-5/3 >= 0 // + 5/3

4*x >= 5/3 // : 4

x >= 5/3/4

x >= 5/12

x in <5/12:+oo)

4*x-5/3-1 > 0

x in (-oo:5/12)

-(4*x)-(-5/3)-1 > 0

abs(4*x-5/3)-1 > 0

/ | -(4*x)-(-5/3)-1 > 0 i x in (-oo:5/12) | 4*x-5/3-1 > 0 i x in <5/12:+oo)

x in (-oo:5/12)

-(4*x)-(-5/3)-1 > 0

2/3-4*x > 0 // - 2/3

-4*x > -2/3 // : -4

x < -2/3/(-4)

x < 1/6

x in <5/12:+oo)

4*x-5/3-1 > 0

4*x-8/3 > 0 // + 8/3

4*x > 8/3 // : 4

x > 8/3/4

x > 2/3

x in (-oo:1/6) U (2/3:+oo)

(-oo:1/6) U (2/3:+oo)

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