a=10-(3a+2)

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Solution for a=10-(3a+2) equation: 



a=10-(3a+2)

We move all terms to the left:

a-(10-(3a+2))=0



We calculate terms in parentheses: -(10-(3a+2)), so:

10-(3a+2)

determiningTheFunctionDomain
-(3a+2)+10

We get rid of parentheses

-3a-2+10

We add all the numbers together, and all the variables

-3a+8

Back to the equation:

-(-3a+8)



We get rid of parentheses

a+3a-8=0

We add all the numbers together, and all the variables

4a-8=0

We move all terms containing a to the left, all other terms to the right

4a=8

a=8/4

a=2

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