a=(j+k)h/2

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Solution for a=(j+k)h/2 equation: 


x in (-oo:+oo)

a = (h*(j+k))/2 // - (h*(j+k))/2

a-((h*(j+k))/2) = 0

(-1*h*(j+k))/2+a = 0

(-1*h*(j+k))/2+(2*a)/2 = 0

2*a-1*h*(j+k) = 0

2*a-(h*j)-(h*k) = 0

(2*a-(h*j)-(h*k))/2 = 0

(2*a-(h*j)-(h*k))/2 = 0 // * 2

2*a-(h*j)-(h*k) = 0

x belongs to the empty set

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