8(y-4)+4(y+3)=16

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Solution for 8(y-4)+4(y+3)=16 equation:


Simplifying
8(y + -4) + 4(y + 3) = 16

Reorder the terms:
8(-4 + y) + 4(y + 3) = 16
(-4 * 8 + y * 8) + 4(y + 3) = 16
(-32 + 8y) + 4(y + 3) = 16

Reorder the terms:
-32 + 8y + 4(3 + y) = 16
-32 + 8y + (3 * 4 + y * 4) = 16
-32 + 8y + (12 + 4y) = 16

Reorder the terms:
-32 + 12 + 8y + 4y = 16

Combine like terms: -32 + 12 = -20
-20 + 8y + 4y = 16

Combine like terms: 8y + 4y = 12y
-20 + 12y = 16

Solving
-20 + 12y = 16

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '20' to each side of the equation.
-20 + 20 + 12y = 16 + 20

Combine like terms: -20 + 20 = 0
0 + 12y = 16 + 20
12y = 16 + 20

Combine like terms: 16 + 20 = 36
12y = 36

Divide each side by '12'.
y = 3

Simplifying
y = 3

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