a2=6(2)2=10

Solution for a2=6(2)2=10 equation:

a2=6(2)2=10

We move all terms to the left:

a2-(6(2)2)=0

determiningTheFunctionDomain
a2-622=0

We add all the numbers together, and all the variables

a^2-622=0

a = 1; b = 0; c = -622;
Δ = b2-4ac
Δ = 02-4·1·(-622)
Δ = 2488
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2488}=\sqrt{4*622}=\sqrt{4}*\sqrt{622}=2\sqrt{622}$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{622}}{2*1}=\frac{0-2\sqrt{622}}{2}
=-\frac{2\sqrt{622}}{2}
=-\sqrt{622}
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{622}}{2*1}=\frac{0+2\sqrt{622}}{2}
=\frac{2\sqrt{622}}{2}
=\sqrt{622}
$