6(-10b+2)=72

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Solution for 6(-10b+2)=72 equation: 



6(-10b+2)=72

We move all terms to the left:

6(-10b+2)-(72)=0

We multiply parentheses

-60b+12-72=0

We add all the numbers together, and all the variables

-60b-60=0

We move all terms containing b to the left, all other terms to the right

-60b=60

b=60/-60

b=-1

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