(1/5)(5a+25)=(1/3)(9a+27)

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Solution for (1/5)(5a+25)=(1/3)(9a+27) equation: 



(1/5)(5a+25)=(1/3)(9a+27)

We move all terms to the left:

(1/5)(5a+25)-((1/3)(9a+27))=0



Domain of the equation: 5)(5a+25)!=0

a∈R





Domain of the equation: 3)(9a+27))!=0

a∈R



We add all the numbers together, and all the variables

(+1/5)(5a+25)-((+1/3)(9a+27))=0

We multiply parentheses ..

(+5a^2+1/5*25)-((+1/3)(9a+27))=0

We calculate fractions


((+5a^2+1*3)(9a+27)))/375a^2+()/375a^2=0

We can not solve this equation

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