a+a-2=(a+3)-a-1

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Solution for a+a-2=(a+3)-a-1 equation: 



a+a-2=(a+3)-a-1

We move all terms to the left:

a+a-2-((a+3)-a-1)=0

We add all the numbers together, and all the variables

2a-((a+3)-a-1)-2=0



We calculate terms in parentheses: -((a+3)-a-1), so:

(a+3)-a-1

We add all the numbers together, and all the variables

-1a+(a+3)-1

We get rid of parentheses

-1a+a+3-1

We add all the numbers together, and all the variables

2

Back to the equation:

-(2)



We add all the numbers together, and all the variables

2a-4=0

We move all terms containing a to the left, all other terms to the right

2a=4

a=4/2

a=2

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