X=(2z-3)/4z

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Solution for X=(2z-3)/4z equation: 



X=(2X-3)/4X

We move all terms to the left:

X-((2X-3)/4X)=0



Domain of the equation: 4X)!=0

X!=0/1

X!=0

X∈R



We multiply all the terms by the denominator


X*4X)-((2X-3)=0

Wy multiply elements

4X^2=0

a = 4; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·4·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$X=\frac{-b}{2a}=\frac{0}{8}=0$

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