a+7/a+4-1=a+10/2a+8

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Solution for a+7/a+4-1=a+10/2a+8 equation:


D( a )

a = 0

a = 0

a = 0

a in (-oo:0) U (0:+oo)

a+7/a-1+4 = a+(10/2)*a+8 // - a+(10/2)*a+8

a-a-((10/2)*a)+7/a-8-1+4 = 0

a-a-5*a+7/a-8-1+4 = 0

7*a^-1-5*a^1-5*a^0 = 0

(7*a^0-5*a^2-5*a^1)/(a^1) = 0 // * a^2

a^1*(7*a^0-5*a^2-5*a^1) = 0

a^1

7-5*a^2-5*a = 0

7-5*a^2-5*a = 0

DELTA = (-5)^2-(-5*4*7)

DELTA = 165

DELTA > 0

a = (165^(1/2)+5)/(-5*2) or a = (5-165^(1/2))/(-5*2)

a = (165^(1/2)+5)/(-10) or a = (5-165^(1/2))/(-10)

a in { (165^(1/2)+5)/(-10), (5-165^(1/2))/(-10)}

a in { (165^(1/2)+5)/(-10), (5-165^(1/2))/(-10) }

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