x+(z+2)+(z+4)=96

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Solution for x+(z+2)+(z+4)=96 equation:


Simplifying
x + (z + 2) + (z + 4) = 96

Reorder the terms:
x + (2 + z) + (z + 4) = 96

Remove parenthesis around (2 + z)
x + 2 + z + (z + 4) = 96

Reorder the terms:
x + 2 + z + (4 + z) = 96

Remove parenthesis around (4 + z)
x + 2 + z + 4 + z = 96

Reorder the terms:
2 + 4 + x + z + z = 96

Combine like terms: 2 + 4 = 6
6 + x + z + z = 96

Combine like terms: z + z = 2z
6 + x + 2z = 96

Solving
6 + x + 2z = 96

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + x + -6 + 2z = 96 + -6

Reorder the terms:
6 + -6 + x + 2z = 96 + -6

Combine like terms: 6 + -6 = 0
0 + x + 2z = 96 + -6
x + 2z = 96 + -6

Combine like terms: 96 + -6 = 90
x + 2z = 90

Add '-2z' to each side of the equation.
x + 2z + -2z = 90 + -2z

Combine like terms: 2z + -2z = 0
x + 0 = 90 + -2z
x = 90 + -2z

Simplifying
x = 90 + -2z

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