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a+5=3/5a
We move all terms to the left:
a+5-(3/5a)=0
Domain of the equation: 5a)!=0We add all the numbers together, and all the variables
a!=0/1
a!=0
a∈R
a-(+3/5a)+5=0
We get rid of parentheses
a-3/5a+5=0
We multiply all the terms by the denominator
a*5a+5*5a-3=0
Wy multiply elements
5a^2+25a-3=0
a = 5; b = 25; c = -3;
Δ = b2-4ac
Δ = 252-4·5·(-3)
Δ = 685
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-\sqrt{685}}{2*5}=\frac{-25-\sqrt{685}}{10} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+\sqrt{685}}{2*5}=\frac{-25+\sqrt{685}}{10} $
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