a+2(3a-6)=30-2(a-3)

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Solution for a+2(3a-6)=30-2(a-3) equation: 



a+2(3a-6)=30-2(a-3)

We move all terms to the left:

a+2(3a-6)-(30-2(a-3))=0

We multiply parentheses

a+6a-(30-2(a-3))-12=0



We calculate terms in parentheses: -(30-2(a-3)), so:

30-2(a-3)

determiningTheFunctionDomain
-2(a-3)+30

We multiply parentheses

-2a+6+30

We add all the numbers together, and all the variables

-2a+36

Back to the equation:

-(-2a+36)



We add all the numbers together, and all the variables

7a-(-2a+36)-12=0

We get rid of parentheses

7a+2a-36-12=0

We add all the numbers together, and all the variables

9a-48=0

We move all terms containing a to the left, all other terms to the right

9a=48

a=48/9

a=5+1/3

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