Z-3(z+4)=-2z+12

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Solution for Z-3(z+4)=-2z+12 equation: 



-3(Z+4)=-2Z+12

We move all terms to the left:

-3(Z+4)-(-2Z+12)=0

We multiply parentheses

-3Z-(-2Z+12)-12=0

We get rid of parentheses

-3Z+2Z-12-12=0

We add all the numbers together, and all the variables

-1Z-24=0

We move all terms containing Z to the left, all other terms to the right

-Z=24

Z=24/-1

Z=-24

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