I1/3(15x-12)=9x-6

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Solution for I1/3(15x-12)=9x-6 equation: 



1/3(15I-12)=9I-6

We move all terms to the left:

1/3(15I-12)-(9I-6)=0



Domain of the equation: 3(15I-12)!=0

I∈R



We get rid of parentheses

1/3(15I-12)-9I+6=0

We multiply all the terms by the denominator


-9I*3(15I-12)+6*3(15I-12)+1=0

Wy multiply elements

-27I^2(1+18I(1+1=0

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