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=Y2-Y-6
We move all terms to the left:
-(Y2-Y-6)=0
We add all the numbers together, and all the variables
-(+Y^2-1Y-6)=0
We get rid of parentheses
-Y^2+1Y+6=0
We add all the numbers together, and all the variables
-1Y^2+Y+6=0
a = -1; b = 1; c = +6;
Δ = b2-4ac
Δ = 12-4·(-1)·6
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-5}{2*-1}=\frac{-6}{-2} =+3 $$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+5}{2*-1}=\frac{4}{-2} =-2 $
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