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20-(x+3)=2(x+1)
We move all terms to the left:
20-(x+3)-(2(x+1))=0
We get rid of parentheses
-x-(2(x+1))-3+20=0
We calculate terms in parentheses: -(2(x+1)), so:We add all the numbers together, and all the variables
2(x+1)
We multiply parentheses
2x+2
Back to the equation:
-(2x+2)
-1x-(2x+2)+17=0
We get rid of parentheses
-1x-2x-2+17=0
We add all the numbers together, and all the variables
-3x+15=0
We move all terms containing x to the left, all other terms to the right
-3x=-15
x=-15/-3
x=+5
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