2x-22+3x=8(x-3)+8

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Solution for 2x-22+3x=8(x-3)+8 equation: 



2x-22+3x=8(x-3)+8

We move all terms to the left:

2x-22+3x-(8(x-3)+8)=0

We add all the numbers together, and all the variables

5x-(8(x-3)+8)-22=0



We calculate terms in parentheses: -(8(x-3)+8), so:

8(x-3)+8

We multiply parentheses

8x-24+8

We add all the numbers together, and all the variables

8x-16

Back to the equation:

-(8x-16)



We get rid of parentheses

5x-8x+16-22=0

We add all the numbers together, and all the variables

-3x-6=0

We move all terms containing x to the left, all other terms to the right

-3x=6

x=6/-3

x=-2

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