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=Y+2/5Y-7
We move all terms to the left:
-(Y+2/5Y-7)=0
Domain of the equation: 5Y-7)!=0We get rid of parentheses
Y∈R
-Y-2/5Y+7=0
We multiply all the terms by the denominator
-Y*5Y+7*5Y-2=0
Wy multiply elements
-5Y^2+35Y-2=0
a = -5; b = 35; c = -2;
Δ = b2-4ac
Δ = 352-4·(-5)·(-2)
Δ = 1185
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-\sqrt{1185}}{2*-5}=\frac{-35-\sqrt{1185}}{-10} $$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+\sqrt{1185}}{2*-5}=\frac{-35+\sqrt{1185}}{-10} $
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