3(2e+5)-2(5e-2)=35

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Solution for 3(2e+5)-2(5e-2)=35 equation: 



3(2e+5)-2(5e-2)=35

We move all terms to the left:

3(2e+5)-2(5e-2)-(35)=0

We multiply parentheses

6e-10e+15+4-35=0

We add all the numbers together, and all the variables

-4e-16=0

We move all terms containing e to the left, all other terms to the right

-4e=16

e=16/-4

e=-4

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